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Sullivan  04 apcalc4e 45342 ch02 166 233 5pp  August 7, 2023  12:54



               222     Chapter 2 • The Derivative and Its Properties

                                                   Application: Simple Harmonic Motion

                                                   Simple harmonic motion is a repetitive motion that can be modeled by a
                                                   trigonometric function. A swinging pendulum and an oscillating spring are examples
                                                   of simple harmonic motion.

                                                    EXAMPLE 6 Analyzing Simple Harmonic Motion
                                                   length l of the spring after t seconds is modeled by the function l(t) = 2 + cos t.Copy.
                                                   An object hangs on a spring, making the spring 2 m long in its equilibrium position. See
                                                   Figure 32. If the object is pulled down 1 m and released, it oscillates up and down. The
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                                                   (a) How does the length of the spring vary?
                       1                           (b) Find the velocity of the object.
                                                   (c) At what position is the speed of the object a maximum?
                                  Equ
                       2          Equilibrium      (d) Find the acceleration of the object.
                                                   (e) At what position is the acceleration equal to 0?
                                  t
                       3          t  0
                                                   Solution
                                                   (a) Since l(t) = 2 + cos t and −1 ≤ cos t ≤ 1, the length of the spring varies between
               Figure 32
                                                   1 and 3 m.
                                                   (b) The velocity v of the object is
                                                                                  d
                                                                            ′
                                                                        v =l (t) =  (2 + cos t) = −sin t
                                                                                 dt
                                                   (c) Speed is the absolute value of velocity. Since v = −sin t, the speed of the object
                                                   is |v| = |−sin t| = |sin t| . Since −1 ≤ sin t ≤ 1, the object moves the fastest
                                                   when |v| = |sin t| = 1. This occurs when sin t = ±1 or, equivalently, when cos t = 0.
                                                   So, the speed is a maximum when l(t) = 2, that is, when the spring is at the equilibrium
                                                   position.
                                                   (d) The acceleration a of the object is given by

                                                                               d       d
                                                                         ′′      ′
                                                                     a =l (t) =  l (t) =  (−sin t) = −cos t
                                                                              dt      dt
                                                   (e) Since a = −cos t, the acceleration is zero when cos t = 0. So, a = 0 when l(t) = 2,
                                                   that is, when the spring is at the equilibrium position. This is the same time at which the
                                                   speed is maximum.

                                                      Figure 33 shows the graphs of the length of the spring y =l(t), the velocity y = v(t),
                                                   and the acceleration y = a(t).


                                                              y
                                                              3     y   l(t)

                                                              2                                        Equilibrium
                                                                                                        position
                                                              1


                                                                                                       t
                                                             1     y   a(t)   y   v(t)

                                                   Figure 33 y = l(t)(blue), y = v(t)(red), y = a(t)(green)


                                                    NOW WORK   Problem 65.

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