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Sullivan  04 apcalc4e 45342 ch02 166 233 5pp  August 7, 2023  12:54



               174     Chapter 2 • The Derivative and Its Properties

                                                    EXAMPLE 7 Finding an Equation of a Tangent Line
                                                                              √
                                                   (a) Find the derivative of f (x) =  2x at x = 8.
                                                   (b) Use the derivative f (8) to find an equation of the tangent line to the graph
                                                                       ′
                                                      of f at the point (8, 4).
                                                   Solution
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                                                   (a) The derivative of f at 8 is
                                                                                 √             √        √
                                                                 f (x) − f (8)    2x − 4        2x − 4   2x + 4
                                                       f (8) = lim         = lim        = lim         √
                                                        ′
                                                             x→8    x − 8  ↑  x→8 x − 8  ↑  x→8  (x − 8)  2x + 4
                                                                         √
                 y                                                  f (8) =  2 · 8 = 4  Rationalize
                                                                                    the numerator.
                                                                     2x − 16             2(x − 8)            2      1
                 6                     1
                                    y  !x " 2             = lim       √        = lim       √        = lim √      =
                                       4                     x→8 (x − 8)  2x + 4  x→8 (x − 8)  2x + 4  x→8  2x + 4  4
                                                                                                                  1
                             (8, 4)   f (x)    2x  (b) The slope of the tangent line to the graph of f at the point (8, 4) is f (8) = . Using
                                                                                                            ′
                 4
                                                                                                                  4
                                                   the point-slope form of a line, we get
                                                                            ′
                                                                    y − 4 = f (8)(x − 8)  y − y = m(x − x 1 )
                 2                                                                           1
                                                                           1                   1
                                                                                          ′
                                                                    y − 4 =  (x − 8)     f (8) =
                                                                           4                   4
                                                                           1
                         4       8      12  x                          y =  x + 2
                                                                           4
               Figure 6                               The graphs of f and the tangent line to the graph of f at (8, 4) are shown in Figure 6.
                                                                             R
                                                    NOW WORK   Problem 15 and AP Practice Problem 4.
                                                                Approximating the Derivative of a Function Represented
                                                    EXAMPLE 8
                                                                by a Table
                                                   The table below lists several values of a function y = f (x) that is continuous on the
                                                   interval [−1, 7] and has a derivative at each number in the interval (−1, 7). Approximate
                                                   the derivative of f at 2.
                                                                             x   0  1   2  4   6
                                                                            f (x)  0  3  12  32  72

                                                   Solution
                                                   There are several ways to approximate the derivative of a function defined by a table.
                                                   Each uses an average rate of change to approximate the rate of change of f at 2, which
                                                   is the derivative of f at 2.
                                                    • Using the average rate of change from 2 to 4, we have
                                                                            f (4) − f (2)  32 − 12
                                                                                      =        = 10
                                                                              4 − 2        2
                                                      With this choice, f (2) is approximately 10.
                                                                      ′
                                                    • Using the average rate of change from 1 to 2, we have

                                                                             f (2) − f (1)  12 − 3
                                                                                       =       = 9
                                                                               2 − 1       1
                                                      With this choice, f (2) is approximately 9.
                                                                      ′
                                                    • A third approximation can be found by averaging the above two approximations.
                                                                              10 + 9  19
                                                      Then f (2) is approximately   =   .
                                                            ′
                                                                                2     2

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